Put each linear factor equal to (0) (to apply the zero product rule). Factorize (ax2+bx+c) into two linear factors. Make the given equation free from fractions and radicals and put it into the standard form (ax2+bx+c0.) Step 2. If you misunderstand something I said, just post a comment. Method of Solving a Quadratic Equation by Factorizing: Step 1. I can see that -12 * 1 makes -11 which is not what I want so I go with 12 * -1. If a quadratic equation can be factored, it is written as a product of linear terms. Factoring means finding expressions that can be multiplied together to give the expression on one side of the equation. I can clearly see that 12 is close to 11 and all I need is a change of 1. Often the easiest method of solving a quadratic equation is factoring. My other method is straight out recognising the middle terms. Here we see 6 factor pairs or 12 factors of -12. What you need to do is find all the factors of -12 that are integers. I use a pretty straightforward mental method but I'll introduce my teacher's method of factors first. So the problem is that you need to find two numbers (a and b) such that the sum of a and b equals 11 and the product equals -12. Sal solves the equation s2-2s-350 by factoring the expression on the left as (s+5)(s-7) and finding the s-values that make each factor equal to zero. This hopefully answers your last question. The -4 at the end of the equation is the constant. In the standard form of quadratic equations, there are three parts to it: ax^2 + bx + c where a is the coefficient of the quadratic term, b is the coefficient of the linear term, and c is the constant.
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